MHT CET · Physics · Mechanical Properties of Fluids
The surface energy of a liquid drop is ' \(U\) '. It splits up into 512 equal droplets. The surface energy becomes
- A \(8 \mathrm{U}\)
- B \(6 \mathrm{U}\)
- C \(4 \mathrm{U}\)
- D \(2 \mathrm{U}\)
Answer & Solution
Correct Answer
(A) \(8 \mathrm{U}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{4}{3} \pi R^3=512 \times \frac{4}{3} \pi r^3 \\ & \therefore r=\frac{R}{8} \\ & U=4 \pi R^2 T \\ & U^{\prime}=512 \times 4 \pi r^2 T \\ & =512 \times \frac{4 \pi R^2 T}{64}=8\left(4 \pi R^2 T\right)=8 U\end{aligned}\)
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