MHT CET · Physics · Gravitation
The speed with which the earth would have to rotate about its axis so that a person on the equator would weigh \(\frac{1}{6}\) th as much as at present is ( \(g=\) gravitational acceleration, \(R=\) equatorial radius of the earth)
- A \(\sqrt{\frac{5}{6} \frac{g}{R}}\)
- B \(\sqrt{\frac{1}{6} \frac{g}{R}}\)
- C \(\sqrt{\frac{6}{5} \frac{R}{g}}\)
- D \(\sqrt{\frac{6}{5}} g R\)
Answer & Solution
Correct Answer
(A) \(\sqrt{\frac{5}{6} \frac{g}{R}}\)
Step-by-step Solution
Detailed explanation
\(W' = W - m\omega^2 R\) \(\frac{1}{6} mg = mg - m\omega^2 R\)
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