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MHT CET · Physics · Gravitation

The speed with which the earth would have to rotate about its axis so that a person on the equator would weigh \(\frac{1}{6}\) th as much as at present is ( \(g=\) gravitational acceleration, \(R=\) equatorial radius of the earth)

  1. A \(\sqrt{\frac{5}{6} \frac{g}{R}}\)
  2. B \(\sqrt{\frac{1}{6} \frac{g}{R}}\)
  3. C \(\sqrt{\frac{6}{5} \frac{R}{g}}\)
  4. D \(\sqrt{\frac{6}{5}} g R\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt{\frac{5}{6} \frac{g}{R}}\)

Step-by-step Solution

Detailed explanation

\(W' = W - m\omega^2 R\) \(\frac{1}{6} mg = mg - m\omega^2 R\)