MHT CET · Physics · Thermal Properties of Matter
The side of a copper cube is \(1 \mathrm{~m}\) at \(0^{\circ} \mathrm{C}\). What will be the change in its volume, when it is heated to \(100^{\circ} \mathrm{C}\) ? \(\left[\alpha_{\text {copper }}=18 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right]\)
- A \(45 \times 10^{-4} \mathrm{~m}^3\)
- B \(54 \times 10^{-4} \mathrm{~m}^3\)
- C \(34 \times 10^{-4} \mathrm{~m}^3\)
- D \(64 \times 10^{-4} \mathrm{~m}^3\)
Answer & Solution
Correct Answer
(B) \(54 \times 10^{-4} \mathrm{~m}^3\)
Step-by-step Solution
Detailed explanation
In volumetric expansion for a cube, Change in volume \(\Delta \mathrm{V}=\mathrm{V} 3 \alpha \Delta \mathrm{T}\)
\(\begin{aligned}
& \Delta V=3 \times 18 \times 10^{-6} \times 100 \\
& \Delta V=54 \times 10^{-4} \mathrm{~m}^3
\end{aligned}\)
\(\begin{aligned}
& \Delta V=3 \times 18 \times 10^{-6} \times 100 \\
& \Delta V=54 \times 10^{-4} \mathrm{~m}^3
\end{aligned}\)
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