MHT CET · Physics · Kinetic Theory of Gases
The rms speed of a gas molecule is ' \(\mathrm{V}\) ' at pressure ' \(\mathrm{P}\) '. If the pressure is increased by two time, then the rms speed of the gas molecule at the same temperature will be
- A \(\mathrm{V}\)
- B \(\sqrt{2} \mathrm{~V}\)
- C \(\frac{\mathrm{V}}{3}\)
- D \(\frac{\mathrm{V}}{2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{V}\)
Step-by-step Solution
Detailed explanation
Since temperature remains constant, there will be no change in r.m.s velocity.
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