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MHT CET · Physics · Kinetic Theory of Gases

The rms speed of a gas molecule is ' \(\mathrm{V}\) ' at pressure ' \(\mathrm{P}\) '. If the pressure is increased by two time, then the rms speed of the gas molecule at the same temperature will be

  1. A \(\mathrm{V}\)
  2. B \(\sqrt{2} \mathrm{~V}\)
  3. C \(\frac{\mathrm{V}}{3}\)
  4. D \(\frac{\mathrm{V}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{V}\)

Step-by-step Solution

Detailed explanation

Since temperature remains constant, there will be no change in r.m.s velocity.
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