MHT CET · Physics · Mathematics in Physics
The resultant of two vectors \(\vec{A}\) and \(\vec{B}\) is \(\vec{C}\). If the magnitude of \(\vec{B}\) is doubled, the new resultant vector becomes perpendicular to \(\vec{A}\), then the magnitude of \(\overrightarrow{\mathrm{C}}\) is
- A \(4 B\)
- B 3 B
- C B
- D 2 B
Answer & Solution
Correct Answer
(C) B
Step-by-step Solution
Detailed explanation
\((\vec{A} + 2\vec{B}) \cdot \vec{A} = 0\) \(A^2 + 2\vec{A} \cdot \vec{B} = 0\)
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