MHT CET · Physics · Semiconductors
The resultant gate and its Boolean expression in the given circuit is
- A \(\mathrm{NOR}, \overline{\mathrm{A}+\mathrm{B}}\)
- B \(AND, A.B\)
- C \(\text { OR, A } + B\)
- D \(NAND, \overline{\mathrm{AB}}\)
Answer & Solution
Correct Answer
(B) \(AND, A.B\)
Step-by-step Solution
Detailed explanation
Truth table:
\(\begin{array}{|l|l|l|l|l|}
\hline A & B & C & D & Y \\
\hline 0 & 0 & 1 & 1 & 0 \\
\hline 0 & 1 & 1 & 0 & 0 \\
\hline 1 & 0 & 0 & 1 & 0 \\
\hline 1 & 1 & 0 & 0 & 1 \\
\hline
\end{array}\)
This is truth table of AND gate.
\(\therefore \mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
\(\begin{array}{|l|l|l|l|l|}
\hline A & B & C & D & Y \\
\hline 0 & 0 & 1 & 1 & 0 \\
\hline 0 & 1 & 1 & 0 & 0 \\
\hline 1 & 0 & 0 & 1 & 0 \\
\hline 1 & 1 & 0 & 0 & 1 \\
\hline
\end{array}\)
This is truth table of AND gate.
\(\therefore \mathrm{Y}=\mathrm{A} \cdot \mathrm{B}\)
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