MHT CET · Physics · Alternating Current
The resonant frequency of an \(L-C\) circuit is
- A \(\frac{1}{2 \pi \sqrt{L C}}\)
- B \(\frac{1}{2 \pi} \sqrt{\frac{L}{C}}\)
- C \(\frac{1}{2 \pi} \sqrt{\frac{L}{C}}\)
- D \(\frac{1}{2 \pi} \sqrt{\frac{C}{L}}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2 \pi \sqrt{L C}}\)
Step-by-step Solution
Detailed explanation
Resonant frequency (or natural frequency) of an \(L-C\) circuit is given as
\(
v_{0}=\left(\frac{1}{2 \pi \sqrt{L C}}\right)
\)
\(
v_{0}=\left(\frac{1}{2 \pi \sqrt{L C}}\right)
\)
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