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MHT CET · Physics · Alternating Current

The resonant frequency of a series LCR circuit is ' \(\mathrm{f}\) '. The circuit is now connected to the sinusoidally alternating e.m.f. of frequency ' \(2 \mathrm{f}^{\prime}\). The new reactance \(\mathrm{X}_{\mathrm{L}}^{\prime}\) and
\(\mathrm{X}_{\mathrm{C}}^{\prime}\) are related as

  1. A \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{4} \mathrm{X}_{\mathrm{L}}^{\prime}\)
  2. B \(\mathrm{X}_{\mathrm{C}}^{\prime}=2 \mathrm{X}_{\mathrm{L}}^{\prime}\)
  3. C \(\mathrm{X}_{\mathrm{C}}^{\prime}=\mathrm{X}_{\mathrm{L}}^{\prime}\)
  4. D \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{2} \mathrm{X}_{\mathrm{L}}^{\prime}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{4} \mathrm{X}_{\mathrm{L}}^{\prime}\)

Step-by-step Solution

Detailed explanation

At resonance: \( X_L = X_C \) New frequency: \( f' = 2f \)