MHT CET · Physics · Alternating Current
The resonant frequency of a series LCR circuit is ' \(\mathrm{f}\) '. The circuit is now connected to the sinusoidally alternating e.m.f. of frequency ' \(2 \mathrm{f}^{\prime}\). The new reactance \(\mathrm{X}_{\mathrm{L}}^{\prime}\) and
\(\mathrm{X}_{\mathrm{C}}^{\prime}\) are related as
- A \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{4} \mathrm{X}_{\mathrm{L}}^{\prime}\)
- B \(\mathrm{X}_{\mathrm{C}}^{\prime}=2 \mathrm{X}_{\mathrm{L}}^{\prime}\)
- C \(\mathrm{X}_{\mathrm{C}}^{\prime}=\mathrm{X}_{\mathrm{L}}^{\prime}\)
- D \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{2} \mathrm{X}_{\mathrm{L}}^{\prime}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{X}_{\mathrm{C}}^{\prime}=\frac{1}{4} \mathrm{X}_{\mathrm{L}}^{\prime}\)
Step-by-step Solution
Detailed explanation
At resonance: \( X_L = X_C \) New frequency: \( f' = 2f \)
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