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MHT CET · Physics · Current Electricity

The resistivity of potentiometer wire is \(40 \times 10^{-8} \Omega m\) and its area of cross-section is 8 \(\times 10^{-6} m^2\). If 0.2 A current is flowing through the wire, the potential gradient of the wire is

  1. A \(0.1\text{ V m} ^{-1}\)
  2. B \(10^{-2}\text{ V m} ^{-1}\)
  3. C \(10^{-3}\text{ V m} ^{-1}\)
  4. D \(10^{-4}\text{ V m} ^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10^{-2}\text{ V m} ^{-1}\)

Step-by-step Solution

Detailed explanation

\(R=\frac{\rho l}{A}\)
\(\therefore \frac{R}{l}=\frac{\rho}{A}=\frac{40 \times 10^{-8}}{8 \times 10^{-6}}=5 \times 10^{-2}\)
\(\frac{V}{l}=\frac{I R}{l}=0.2 \times 5 \times 10^{-2}=10^{-2}\text{ V m} ^{-1}\)