MHT CET · Physics · Current Electricity
The resistance in the left and right gaps of a meter bridge are \(10 \Omega\) and \(30 \Omega\) respectively. If the bridge is balanced, then the distance of the null point from the center of the wire is
- A \(20 \mathrm{~cm}\)
- B \(30 \mathrm{~cm}\)
- C \(25 \mathrm{~cm}\)
- D \(40 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(25 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
The given ratio of resistors is:
\(\frac{P}{Q}=\frac{10}{30}=\frac{1}{3}=\frac{l_1}{l_2}\)
\(\therefore l_2=3 l_1\)
Since, \(l_1+3 l_1=100 \mathrm{~cm}\)
\(\therefore l_1=25 \mathrm{~cm}\)
\(\frac{P}{Q}=\frac{10}{30}=\frac{1}{3}=\frac{l_1}{l_2}\)
\(\therefore l_2=3 l_1\)
Since, \(l_1+3 l_1=100 \mathrm{~cm}\)
\(\therefore l_1=25 \mathrm{~cm}\)
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