MHT CET · Physics · Ray Optics
The refractive index of glass is \(\frac{3}{2}\) and that of water is \(\frac{4}{3}\). The critical angle for a ray
of light going from glass to water is
- A \(\sin ^{-1}\left(\frac{4}{7}\right)\)
- B \(\sin ^{-1}\left(\frac{5}{8}\right)\)
- C \(\sin ^{-1}\left(\frac{2}{3}\right)\)
- D \(\sin ^{-1}\left(\frac{8}{9}\right)\)
Answer & Solution
Correct Answer
(D) \(\sin ^{-1}\left(\frac{8}{9}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \sin C &=\frac{1}{2 \mu_{1}} \\{ }_{2} \mu_{1} &=\frac{\mu_{1}}{\mu_{2}}=\frac{3 / 2}{4 / 3}=\frac{3}{2} \times \frac{3}{4}=\frac{9}{8} \\ \sin C &=\frac{1}{9 / 8}=\frac{8}{9} \\ \therefore C &=\sin ^{-1} \frac{8}{9} \end{aligned}\)
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