MHT CET · Physics · Alternating Current
The reactance of a capacitor is \(\mathrm{X}_{\mathrm{c}}\). If the frequency and the capacitance are doubled, then the new reactance will be
- A \(\frac{X_C}{2}\)
- B \(\mathrm{X}_{\mathrm{c}}\)
- C \(\frac{X_C}{4}\)
- D \(2 \mathrm{X}_{\mathrm{c}}\)
Answer & Solution
Correct Answer
(C) \(\frac{X_C}{4}\)
Step-by-step Solution
Detailed explanation
\(X_c = \frac{1}{2\pi f C}\) \(X_c' = \frac{1}{2\pi (2f) (2C)}\)
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