MHT CET · Physics · Atomic Physics
The ratio of the total energy of the \(2^{\text {nd }}\) orbit electron for the hydrogen atom \(1 \mathrm{H}^1\) to that of helium ion \(\left(\mathrm{He}^{+}\right) 2 \mathrm{He}^4\) is
- A 4
- B 2
- C \(\frac{1}{2}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
\(E_n \propto \frac{Z^2}{n^2}\) \(\frac{E_H}{E_{He^+}} = \frac{Z_H^2/n_H^2}{Z_{He^+}^2/n_{He^+}^2}\)
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