MHT CET · Physics · Atomic Physics
The ratio of the areas of the electron orbits for the second excited state to the first excited state for the hydrogen atom is
- A \(3: 2\)
- B \(9: 4\)
- C 16:81
- D 81:16
Answer & Solution
Correct Answer
(D) 81:16
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & r_n \propto n^2 \Rightarrow A_n \propto n^4 \text { where, } A_n=\text { area } \\ \therefore \quad & \frac{A_3}{A_2}=\left(\frac{3}{2}\right)^4=\frac{81}{16}\end{aligned}\)
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