MHT CET · Physics · Atomic Physics
The ratio of maximum to minimum wavelength in Balmer series hydrogen atom is
- A 36:5
- B 3:4
- C 9:5
- D 5:9
Answer & Solution
Correct Answer
(C) 9:5
Step-by-step Solution
Detailed explanation
Maximum wavelength of Balmer series is given by
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
\(\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}\)
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
\(\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}\)
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