MHT CET · Physics · Mechanical Properties of Solids
The ratio of length of two wires of same material is \(1: 2\) and the ratio of their radii
is \(1: \sqrt{2}\). If they are stretched by the same force, the ratio of increase in their
lengths is
- A \(\sqrt{2}: 2\)
- B \(1: 1\)
- C \(2: \sqrt{2}\)
- D \(1: 2\)
Answer & Solution
Correct Answer
(B) \(1: 1\)
Step-by-step Solution
Detailed explanation
\(Y=\frac{F l}{\pi r^{2} \Delta l}\) or \(\Delta l=\frac{F l}{\pi r^{2} Y}\)
\(\Delta l \propto \frac{l}{r^{2}}, \quad \Delta l^{\prime} \propto \frac{2 l}{(\sqrt{2} r)^{2}}\) or \(\Delta l^{\prime} \propto \frac{l}{r^{2}}\)
\(\therefore \frac{\Delta l}{\Delta l^{\prime}}=1\)
\(\Delta l \propto \frac{l}{r^{2}}, \quad \Delta l^{\prime} \propto \frac{2 l}{(\sqrt{2} r)^{2}}\) or \(\Delta l^{\prime} \propto \frac{l}{r^{2}}\)
\(\therefore \frac{\Delta l}{\Delta l^{\prime}}=1\)
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