MHT CET · Physics · Wave Optics
The ratio of intensities of two waves producing interference is \(9: 4\), then the ratio
of the resultant maximum and minimum intensities will be \(\left(\cos \frac{\pi}{3}=\frac{1}{2}\right)\)
- A \(4: 9\)
- B \(9: 4\)
- C \(25: 1\)
- D \(5: 1\)
Answer & Solution
Correct Answer
(C) \(25: 1\)
Step-by-step Solution
Detailed explanation
\(\frac{I_{1}}{I_{2}}=\frac{9}{4}\)
\(\therefore \frac{a_{1}}{a_{2}}=\frac{3}{2}\)
\(\frac{a_{1}+a_{2}}{a_{1}-a_{2}}=\frac{3+2}{3-2}=\frac{5}{1}\)
\(\therefore \frac{\left(a_{1}+a_{2}\right)^{2}}{\left(a_{1}-a_{2}\right)^{2}}=\frac{25}{1}\)
\(\therefore \frac{a_{1}}{a_{2}}=\frac{3}{2}\)
\(\frac{a_{1}+a_{2}}{a_{1}-a_{2}}=\frac{3+2}{3-2}=\frac{5}{1}\)
\(\therefore \frac{\left(a_{1}+a_{2}\right)^{2}}{\left(a_{1}-a_{2}\right)^{2}}=\frac{25}{1}\)
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