MHT CET · Physics · Atomic Physics
The ratio of angular momentum of an electron in \(\mathrm{n}^{\text {th }}\) orbit of hydrogen atom to the velocity of electron in \(n^{\text {th }}\) orbit is proportional to
- A \(\mathrm{n}^2\)
- B \(\frac{1}{\mathrm{n}^2}\)
- C \(\mathrm{n}^3\)
- D \(\frac{1}{\mathrm{n}^3}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{n}^2\)
Step-by-step Solution
Detailed explanation
\(L = \frac{nh}{2\pi}\) \(v_n = \frac{e^2}{2\epsilon_0nh}\)
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