MHT CET · Physics · Thermal Properties of Matter
The rate of flow of heat through a copper rod with temperature difference \(28^{\circ} \mathrm{C}\) is \(1400 \mathrm{cal} \mathrm{s}^{-1}\). The thermal resistance of copper rod will be
- A \(0.05 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}\)
- B \(0.02 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}\)
- C \(5 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}\)
- D \(2 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}\)
Answer & Solution
Correct Answer
(B) \(0.02 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}\)
Step-by-step Solution
Detailed explanation
Thermal resistance \(=\frac{\text { Temp.difference }}{\text { Thermalcurrent }}=\frac{28}{1400}=0.02{ }^{\circ} \mathrm{Cs} / \mathrm{cal}\)
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