MHT CET · Physics · Current Electricity
The range of voltmeter of resistance ' G ' \(\Omega\) is ' V ' volt. The resistance required to be connected in series with it in order to convert it into a voltmeter of range ' \(n V\) ' volt, will be
- A \((\mathrm{n}-1) \mathrm{G}\)
- B \(\mathrm{G} / \mathrm{n}\)
- C nG
- D \(\frac{\mathrm{G}}{\mathrm{n}}-1\)
Answer & Solution
Correct Answer
(A) \((\mathrm{n}-1) \mathrm{G}\)
Step-by-step Solution
Detailed explanation
Here, The range of a voltmeter of resistance G is V volt. Let, I be the current thruogh it then
\(\mathrm{G}=\frac{\mathrm{V}}{\mathrm{I}} \ldots\) (1)
Now to convert it into voltmeter of range nV , the required resistance will be,
\(\mathrm{R}=\frac{\mathrm{nV}}{\mathrm{I}}=\mathrm{nG}\) (from (1))
Hence, the resistance to be added in series is
\(\mathrm{R}-\mathrm{G}=\mathrm{nG}-\mathrm{G}=(\mathrm{n}-1) \mathrm{G}\)
The resistance \((\mathrm{n}-1) \mathrm{G}\) is to be connected in series with voltmeter of range V in order to convert it into a voltmeter of range nV volt,
\(\mathrm{G}=\frac{\mathrm{V}}{\mathrm{I}} \ldots\) (1)
Now to convert it into voltmeter of range nV , the required resistance will be,
\(\mathrm{R}=\frac{\mathrm{nV}}{\mathrm{I}}=\mathrm{nG}\) (from (1))
Hence, the resistance to be added in series is
\(\mathrm{R}-\mathrm{G}=\mathrm{nG}-\mathrm{G}=(\mathrm{n}-1) \mathrm{G}\)
The resistance \((\mathrm{n}-1) \mathrm{G}\) is to be connected in series with voltmeter of range V in order to convert it into a voltmeter of range nV volt,
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A radioactive element \({ }_{92}^{242} \mathrm{X}\) emits two \(\alpha\) particles, one electron and two positrons. The product nucleus is represented by \({ }_{\mathrm{P}}^{234} \mathrm{Y}\). The value of P isMHT CET 2025 Medium
- When a string of length ' \(l\) ' is divided into three segments of length \(l_1, l_2\) and \(l_3\). The fundamental frequencies of three segments are \(\mathrm{n}_1, \mathrm{n}_2\) and \(\mathrm{n}_3\) respectively. The original fundamental frequency ' \(n\) ' of the string isMHT CET 2023 Medium
- In an LCR circuit, if ' \(V\) ' is the effective value of the applied voltage, \(V_R\) is the voltage across ' \(R\) ', ' \(\mathrm{V}_{\mathrm{L}}\) ' and ' \(\mathrm{V}_{\mathrm{C}}\) ' is the effective voltage across ' L ' and ' C ' respectively thenMHT CET 2024 Easy
- If r.m.s. velocity of hydrogen molecules is 4 times that of an oxygen molecule at \(47^{\circ} \mathrm{C}\), the temperature of hydrogen molecules is (Molecular weight of Hydrogen and Oxygen are 2 and 32 respectively)MHT CET 2025 Medium
- A double slit experiment is immersed in water of refractive index 1.33. The slit separations \(1 \mathrm{~mm}\) and the distance between slit and screen is \(1.33 \mathrm{~m}\). The slits are illuminated by a light of wavelength \(6300 Å\). The fringe width isMHT CET 2021 Hard
- Two parallel conductors carrying unequal currents in the same direction __________MHT CET 2019 Medium
More PYQs from MHT CET
- General solution of the differential equation \(\cos x(1+\cos y) \mathrm{d} x-\sin y(1+\sin x) \mathrm{d} y=0\) isMHT CET 2023 Medium
- For the reaction, \(\mathrm{NO}_{2(\mathrm{~g})}+\mathrm{CO}_{(\mathrm{g})} \longrightarrow \mathrm{NO}_{(\mathrm{g})}+\mathrm{CO}_{2(\mathrm{~g})}\) rate of reaction is proportional to square of [ \(\mathrm{NO}_2\) ] and independent of [CO].
What is the rate law equation?MHT CET 2024 Easy - If \(\mathrm{f}^{\prime}(x)=\tan ^{-1}(\sec x+\tan x),-\frac{\pi}{2} < x < \frac{\pi}{2}\) and \(f(0)=0\), then \(f(1)\) isMHT CET 2023 Medium
- The materials having negative magnetic susceptibility areMHT CET 2020 Easy
- When a d.c voltage of \(200 \mathrm{~V}\) is applied to a coil of self-inductance \(\left(\frac{2 \sqrt{3}}{\pi}\right) \mathrm{H}\), a current of 1A flows through it. But by replacing d.c. source with a.c. source of \(200 \mathrm{~V}\), the current in the coil is reduced to \(0.5 \mathrm{~A}\). Then the frequency of a.c. supply isMHT CET 2021 Hard
- If \(f(x)=b \cdot e^{a x}+a \cdot e^{b x}\), then \(f^{\prime \prime}(0)=\)MHT CET 2022 Easy