The radius of the earth and the radius of orbit around the sun are 6371km and 149×106km respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by

MHT CET · Physics · Units and Dimensions

The radius of the earth and the radius of orbit around the sun are $6371 k m$ and $149 \times 10^{6} k m$ respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by

A $10^{3}$
B $10^{2}$
C $10^{4}$
D $10^{5}$

Verified Solution

Answer & Solution

Correct Answer

(C) $10^{4}$

Step-by-step Solution

Detailed explanation

D = 1.2752 \times 10^{4}

r = 1.49 \times 10^{8}

Order of

D = 4

Order of

r = 8

Difference

= 8 - 4 = 4

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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