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MHT CET · Physics · Kinetic Theory of Gases

The r.m.s. velocity of hydrogen at S.T.P. is ' u ' \(\mathrm{m} / \mathrm{s}\). If the gas is heated at constant pressure till its volume becomes three times, then the final temperature of the gas and the r.m.s. speed are respectively

  1. A \(819 \mathrm{~K},(\sqrt{3}) \mathrm{u} \mathrm{m} / \mathrm{s}\)
  2. B \(\quad 1092 \mathrm{~K}, 3 \mathrm{u} \mathrm{m} / \mathrm{s}\)
  3. C \(819 \mathrm{~K}, \frac{\mathrm{u}}{\sqrt{3}} \mathrm{~m} / \mathrm{s}\)
  4. D \(\quad 1092 \mathrm{~K}, \frac{\mathrm{u}}{3} \mathrm{~m} / \mathrm{s}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(819 \mathrm{~K},(\sqrt{3}) \mathrm{u} \mathrm{m} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

As the process is adiabatic,
\(\frac{V_2}{V_1} =\frac{T_2}{T_1} \Rightarrow \frac{3 V_1}{V_1}=\frac{T_2}{T_1} \)
\( \therefore 3 T_1 =T_2 \)
\( \therefore T_2 =3 \times 273=819 \mathrm{~K}\)
Also,
\(\begin{aligned}
& \mathrm{V}_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}_0}} \\
& \Rightarrow \mathrm{~V}_{\mathrm{rms}} \propto \sqrt{\mathrm{~T}} \\
& \frac{\mathrm{~V}_{\mathrm{rms}}^{\prime}}{\mathrm{V}_{\mathrm{rms}}}=\sqrt{\frac{\mathrm{T}_2}{\mathrm{~T}_1}}
\end{aligned}\)
\(\therefore \quad \mathrm{V}_{\mathrm{rms}}^{\prime}=\mathrm{V}_{\mathrm{rms}} \sqrt{\frac{819}{273}}=\sqrt{3} \mathrm{um} / \mathrm{s} \ldots\left(\text { given } \mathrm{V}_{\mathrm{rms}}=\mathrm{u}\right)\)