MHT CET · Physics · Kinetic Theory of Gases
The quantity \(\frac{\mathrm{PV}}{\mathrm{KT}}\) represents \((\mathrm{K}=\) Boltzmann constant)
- A number of moles of gas.
- B kinetic energy of gas
- C mass of the gas
- D number of molecules of gas in one mole
Answer & Solution
Correct Answer
(D) number of molecules of gas in one mole
Step-by-step Solution
Detailed explanation
\(\mathrm{PV}=\mathrm{nRT}\) \(\mathrm{n}=\frac{\mathrm{PV}}{\mathrm{RT}}\) Number of molecules \(=\mathrm{N}_{\mathrm{A}} \frac{\mathrm{PV}}{\mathrm{RT}}\) \(=\frac{\mathrm{PV}}{\left(\mathrm{R} / \mathrm{N}_{\mathrm{A}}\right) \mathrm{T}}=\frac{\mathrm{PV}}{\mathrm{k}_{\mathrm{B}} \mathrm{T}}\)
where, \(\mathrm{k}_{\mathrm{B}}=\) Boltzmann constant.
where, \(\mathrm{k}_{\mathrm{B}}=\) Boltzmann constant.
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