MHT CET · Physics · Electromagnetic Induction
The pure inductors each of inductance \(6 \mathrm{H}\) are connected as shown in the figure. Their equivalent inductance between the points ' \(\mathrm{P}\) ' and ' \(\mathrm{Q}\) ' is
- A \(0.5 \mathrm{H}\)
- B \(18 \mathrm{H}\)
- C \(6.3 \mathrm{H}\)
- D \(2 \mathrm{H}\)
Answer & Solution
Correct Answer
(D) \(2 \mathrm{H}\)
Step-by-step Solution
Detailed explanation
In the given circuit, one end of each inductor is joined together. Similarly, the other end of each inductor is joined together. Hence the three inductors are connected in parallel. Their equivalent inductance is given by
\(
\begin{aligned}
& \frac{1}{L}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6} \\
& \therefore \mathrm{L}=2 \mathrm{H}
\end{aligned}
\)
\(
\begin{aligned}
& \frac{1}{L}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{3}{6} \\
& \therefore \mathrm{L}=2 \mathrm{H}
\end{aligned}
\)
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