MHT CET · Physics · Kinetic Theory of Gases
The pressure 'P', volume 'V' and temperature 'T' of a gas in a jar 'A' and the gas in other jar ' B ' is at pressure ' 2 P ', volume \({ }^{\prime} \frac{\mathrm{V}}{4}\) ' and temperature \({ }^{\prime} \frac{\mathrm{T}}{4}{ }^{\prime}\). Then the ratio of the number of molecules in jar A and jar B will be
- A \(1: 1\)
- B \(1: 2\)
- C \(2: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(B) \(1: 2\)
Step-by-step Solution
Detailed explanation
\( N \propto \frac{PV}{T} \) \( \frac{N_A}{N_B} = \frac{P_A V_A / T_A}{P_B V_B / T_B} = \frac{P \cdot V / T}{(2P) \cdot (V/4) / (T/4)} \)
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