MHT CET · Physics · Rotational Motion
The power \((\mathrm{P})\) is supplied to a rotating body having moment of inertia ' I ' and angular acceleration ' \(\alpha\) '. Its instantaneous angular velocity ' \(\omega\) ' is
- A \(\mathrm{P}(\mathrm{I} \alpha)^{-1}\)
- B \(\mathrm{P}^{-1}(\mathrm{I} \alpha)^{-1}\)
- C \(\mathrm{P} \alpha^{-1} \mathrm{I}\)
- D PI \(\alpha\)
Answer & Solution
Correct Answer
(A) \(\mathrm{P}(\mathrm{I} \alpha)^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Power }=\frac{\text { Work done }}{\text { time }} \\ & P=\frac{\text { Torque } \times \text { angular displacement }}{\text { time }}=\tau \times \omega \\ & \ldots\left[\because \omega=\frac{\theta}{\mathrm{t}}\right] \\ & \therefore \quad P=I \alpha \omega \\ & \therefore \quad \omega=\frac{\mathrm{P}}{\mathrm{I} \alpha} \\ &=\mathrm{P}(\mathrm{I} \alpha)^{-1} \ldots(\because \tau=\mathrm{I} \alpha)\end{aligned}\)
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