MHT CET · Physics · Alternating Current
The power factor of a CR circuit is \(\frac{1}{\sqrt{2}}\), If the frequency of a. c. signal is halved, then the power factor of the circuit will become
- A \(\frac{1}{\sqrt{3}}\)
- B \(\frac{1}{\sqrt{5}}\)
- C \(\frac{1}{\sqrt{7}}\)
- D \(\frac{1}{\sqrt{11}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{5}}\)
Step-by-step Solution
Detailed explanation
\( \cos\phi_1 = \frac{R}{\sqrt{R^2 + X_C^2}} = \frac{1}{\sqrt{2}} \) \( R^2 = X_C^2 \Rightarrow R = X_C \)
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