MHT CET · Physics · Capacitance
The potential on the plates of capacitor are \(+20 \mathrm{~V}\) and \(-20 \mathrm{~V}\). The charge on the plate is \(40 \mathrm{C}\). The capacitance of the capacitor is
- A \(2 \mathrm{~F}\)
- B \(1 \mathrm{~F}\)
- C \(4 \mathrm{~F}\)
- D \(0.5 \mathrm{~F}\)
Answer & Solution
Correct Answer
(B) \(1 \mathrm{~F}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{V} & =20-(-20)=40 \text { volt } \\ \mathrm{Q} & =40 \mathrm{C} \\ \mathrm{C} & =\frac{\mathrm{Q}}{\mathrm{V}} \\ \therefore \quad \mathrm{C} & =\frac{40}{40} \\ \therefore \quad \mathrm{C} & =1 \mathrm{~F}\end{aligned}\)
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