MHT CET · Physics · Wave Optics
The polarising angle of transparent medium is ' \(\theta\) '. Let the speed of light in the medium be ' \(V\) '. Then the relation between ' \(\theta\) ' and ' \(V\) ' is [ \(\mathrm{C}=\) velocity of light in air]
- A \(\theta=\sin ^{-1}\left(\frac{v}{c}\right)\)
- B \(\theta=\tan ^{-1}\left(\frac{v}{c}\right)\)
- C \(\theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
- D \(\theta=\cos ^{-1}\left(\frac{v}{c}\right)\)
Answer & Solution
Correct Answer
(C) \(\theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
Step-by-step Solution
Detailed explanation
\(\tan\theta = n\) \(n = \frac{C}{V}\)
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