MHT CET · Physics · Wave Optics
The polarising angle for transparent medium is \(\theta, v\) is the speed of light in that medium. Then the relation between \(\theta\) and \(v\) is ( \(c=\) velocity of light in air)
- A \(\theta=\tan ^{-1}\left(\frac{v}{c}\right)\)
- B \(\theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
- C \(\theta=\sin ^{-1}\left(\frac{v}{c}\right)\)
- D \(\theta=\cos ^{-1}\left(\frac{v}{c}\right)\)
Answer & Solution
Correct Answer
(B) \(\theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
Step-by-step Solution
Detailed explanation
\(\tan \theta=\mu=\frac{c}{v}\)
\(\therefore \cot \theta=\frac{v}{c}\)
\(\therefore \theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
\(\therefore \cot \theta=\frac{v}{c}\)
\(\therefore \theta=\cot ^{-1}\left(\frac{v}{c}\right)\)
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