MHT CET · Physics · Wave Optics
The polarising angle for a transparent medium is '\(\theta\)' and 'V' is the speed of light in that medium, then relation between ' \(\theta\) ' and ' \(\mathrm{V}\) ' is (c = velocity of light)
- A \(\theta=\sin ^{-1}\left(\frac{\mathrm{V}}{\mathrm{c}}\right)\)
- B \(\theta=\tan ^{-1}\left(\frac{\mathrm{V}}{\mathrm{c}}\right)\)
- C \(\theta=\cot ^{-1}\left(\frac{\mathrm{v}}{\mathrm{c}}\right)\)
- D \(\theta=\cos ^{-1}\left(\frac{\mathrm{V}}{\mathrm{c}}\right)\)
Answer & Solution
Correct Answer
(C) \(\theta=\cot ^{-1}\left(\frac{\mathrm{v}}{\mathrm{c}}\right)\)
Step-by-step Solution
Detailed explanation
\(\tan \theta = \frac{c}{V}\) \(\cot \theta = \frac{V}{c}\)
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