MHT CET · Physics · Mathematics in Physics
The percentage errors in measurements of mass and speed of a body are \(2 \%\) and
\(3 \%\) respectively. What is the percentage error in kinetic energy of the body?
- A \(9 \%\)
- B \(5 \%\)
- C \(8 \%\)
- D \(0 \%\)
Answer & Solution
Correct Answer
(C) \(8 \%\)
Step-by-step Solution
Detailed explanation
(C)
Given percentage errors in mass and velocity \(=2 \%\) and \(3 \%\) respectively
The kinetic energy of the particle is given by
\(\mathrm{KE}=\frac{\mathrm{mv}^{2}}{2}\)
The percentage error in kinetic energy will be
\(\frac{\Delta \mathrm{m}}{\mathrm{m}} \times 100+2 \frac{\Delta \mathrm{v}}{\mathrm{v}} \times 100\)
\(\begin{array}{l}
=2+6 \\
=8 \%
\end{array}\)
Given percentage errors in mass and velocity \(=2 \%\) and \(3 \%\) respectively
The kinetic energy of the particle is given by
\(\mathrm{KE}=\frac{\mathrm{mv}^{2}}{2}\)
The percentage error in kinetic energy will be
\(\frac{\Delta \mathrm{m}}{\mathrm{m}} \times 100+2 \frac{\Delta \mathrm{v}}{\mathrm{v}} \times 100\)
\(\begin{array}{l}
=2+6 \\
=8 \%
\end{array}\)
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