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MHT CET · Physics · Alternating Current

The peak value of an alternating emf ' \(\mathrm{e}\) ' given by \(\mathrm{e}=\mathrm{e}_0 \cos \omega \mathrm{t}\) is 10 volt and its frequency is \(50 \mathrm{~Hz}\). At time \(\mathrm{t}=\frac{1}{600} \mathrm{~s}\), the instantaneous e.m.f is

  1. A 10 V
  2. B \(\frac{10}{\sqrt{3}} \mathrm{~V}\)
  3. C 5 V
  4. D \(5 \sqrt{3} \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5 \sqrt{3} \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{e}=\mathrm{e}_0 \cos \omega \mathrm{t}=10 \cos 2 \pi \mathrm{ft} \\ & \mathrm{f}=50 \mathrm{~Hz}, \mathrm{t}=\frac{1}{600} \mathrm{~s} \\ & \therefore \mathrm{e}=10 \cos 100 \pi \times \frac{1}{600}=10 \cos \frac{\pi}{6}=5 \sqrt{3} \mathrm{~V}\end{aligned}\)