MHT CET · Physics · Thermodynamics
The \(p-V\) diagram of a system undergoing thermodynamic changes is as shown in the figure. The work done by the system in going from \(A \rightarrow B \rightarrow C\) is \(30 \mathrm{~J}\). If \(68 \mathrm{~J}\) of heat is given to the system, then the change in the internal energy of the system between \(\mathrm{A}\) and \(\mathrm{C}\) is
- A \(34 \mathrm{~J}\)
- B \(55 \mathrm{~J}\)
- C \(55 \mathrm{~J}\)
- D \(55 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(55 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
We know that heat absorbed \(=\Delta Q=68 \mathrm{~J}\),
Work done by the system \(=\Delta W=30 \mathrm{~J}\)
From the first law of thermodynamics, the change in internal energy is given by,
\(\begin{aligned} & \Delta U=\Delta Q-\Delta W \\ & \Rightarrow \Delta U=68-30=38 \mathrm{~J}\end{aligned}\)
Work done by the system \(=\Delta W=30 \mathrm{~J}\)
From the first law of thermodynamics, the change in internal energy is given by,
\(\begin{aligned} & \Delta U=\Delta Q-\Delta W \\ & \Rightarrow \Delta U=68-30=38 \mathrm{~J}\end{aligned}\)
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