MHT CET · Physics · Thermal Properties of Matter
The outer surface of star in the form of a sphere radiates heat as a black body at temperature ' \(T\) '. The total radiant energy per unit area, normal to the direction of incidence, received at a distance ' R ' from the centre of a star of radius ' r ' is ( \(\mathrm{R}>\mathrm{r}\) ) ( \(\sigma=\) Stefan's constant)
- A \(\frac{\sigma r^2 \mathrm{~T}^4}{\mathrm{R}^2}\)
- B \(\frac{\sigma r^2 T^4}{4 \pi R^2}\)
- C \(\frac{\sigma \mathrm{r}^2 \mathrm{~T}^4}{\mathrm{R}^4}\)
- D \(\frac{4 \pi \sigma r^2 T^4}{R^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sigma r^2 \mathrm{~T}^4}{\mathrm{R}^2}\)
Step-by-step Solution
Detailed explanation
\(P = \sigma (4 \pi r^2) T^4\) \(I = \frac{P}{4 \pi R^2} = \frac{\sigma (4 \pi r^2) T^4}{4 \pi R^2} = \frac{\sigma r^2 T^4}{R^2}\)
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