MHT CET · Physics · Atomic Physics
The orbital frequency of an electron in the hydrogen atom is proportional to
- A \(n^{3}\)
- B \(n^{-3}\)
- C \(n^{1}\)
- D \(n^{0}\)
Answer & Solution
Correct Answer
(B) \(n^{-3}\)
Step-by-step Solution
Detailed explanation
Time period of electron, \(T=\frac{4 \varepsilon_{0}^{2} n^{3} h^{3}}{m Z^{2} e^{4}}\)
\(\therefore\)
\(T \propto n^{3}\)
\(\therefore \quad \frac{1}{\text { frequency }(f)} \propto n^{3}\)
or \(f \propto n^{-3}\)
\(\therefore\)
\(T \propto n^{3}\)
\(\therefore \quad \frac{1}{\text { frequency }(f)} \propto n^{3}\)
or \(f \propto n^{-3}\)
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