MHT CET · Physics · Alternating Current
The numbers of turns in the primary and the secondary of a transformer are 1000 and 3000 respectively. If \(80 \mathrm{~V}\) a.c. is applied to the primary coil of the transformer, then the potential difference per turn of the secondary coil would be
- A \(240 \mathrm{~V}\)
- B \(2400 \mathrm{~V}\)
- C \(0.24 \mathrm{~V}\)
- D \(0.08 \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(0.08 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(\frac{E_p}{E_s}=\frac{N_p}{N_s}\)
\(\frac{80}{E_{\mathrm{s}}}=\frac{1000}{3000}\)
\(E_s=240 \mathrm{~V}\)
\(\therefore \quad E_{\mathrm{s}}\) per turn \(=\frac{240}{3000}=0.08 \mathrm{~V}\)
\(\frac{80}{E_{\mathrm{s}}}=\frac{1000}{3000}\)
\(E_s=240 \mathrm{~V}\)
\(\therefore \quad E_{\mathrm{s}}\) per turn \(=\frac{240}{3000}=0.08 \mathrm{~V}\)
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