MHT CET · Physics · Electromagnetic Induction
The mutual inductance of a pair of coils, each of ' \(\mathrm{N}\) ' turns, is ' \(\mathrm{M}\) ' henry. If a current of ' \(\mathrm{I}\) ' ampere in one of the coils is brought to zero in ' \(\mathrm{t}\) ' second, the e. m. f. induced per turn in the other coil in volt is
- A \(\frac{\text { MI }}{t}\)
- B \(\frac{\mathrm{NMI}}{\mathrm{t}}\)
- C \(\frac{\mathrm{NM}}{\mathrm{It}}\)
- D \(\frac{\mathrm{MI}}{\mathrm{Nt}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\text { MI }}{t}\)
Step-by-step Solution
Detailed explanation
Emf induced due to mutual inductance per coil, \(\mathrm{e}=\frac{\mathrm{M} \Delta \mathrm{I}}{\Delta \mathrm{t}}\)
Here, the current changes from I to zero in time \(\mathrm{t}\) seconds.
\(
\therefore \mathrm{e}=\frac{\mathrm{MI}}{\mathrm{t}}
\)
Here, the current changes from I to zero in time \(\mathrm{t}\) seconds.
\(
\therefore \mathrm{e}=\frac{\mathrm{MI}}{\mathrm{t}}
\)
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