MHT CET · Physics · Rotational Motion
The moments of inertia of two freely rotating bodies \(A\) and \(B\) are \(I_{A}\) and \(I_{B}\) respectively. \(I_{A}>I_{B}\) and their angular momenta are equal. If \(K_{A}\) and \(K_{B}\) are their kinetic energies, then
- A \(K_{A}=K_{B}\)
- B \(K_{A} \neq K_{B}\)
- C \(K_{A} < K_{B}\)
- D \(K_{A}=2 K_{B}\)
Answer & Solution
Correct Answer
(C) \(K_{A} < K_{B}\)
Step-by-step Solution
Detailed explanation
Kinetic energy \(E=\frac{L^{2}}{2 I}\) If angular momenta are equal, then \(E \propto \frac{1}{I}\) Kinetic energy \(E=K\) (given in problem)
\(\text { If } I_{A}>I_{B} \text { then } K_{A} < K_{B}\)
\(\text { If } I_{A}>I_{B} \text { then } K_{A} < K_{B}\)
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