MHT CET · Physics · Rotational Motion
The moment of inertia of a thin uniform rod of mass ' \(M\) ' and length ' \(L\) ', about an axis perpendicular to length of the rod and at a distance ' \(\mathrm{L} / 4\) ' from one end is
- A \(\frac{\mathrm{ML}^2}{6}\)
- B \(\frac{\mathrm{ML}^2}{12}\)
- C \(\frac{7 \mathrm{ML}^2}{24}\)
- D \(\frac{7 \mathrm{ML}^2}{48}\)
Answer & Solution
Correct Answer
(D) \(\frac{7 \mathrm{ML}^2}{48}\)
Step-by-step Solution
Detailed explanation
\(I_{CM} = \frac{1}{12}ML^2\) \(d = \frac{L}{2} - \frac{L}{4} = \frac{L}{4}\)
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