MHT CET · Physics · Rotational Motion
The moment of inertia of a solid sphere of mass ' \(m\) ' and radius ' \(R\) ' about its diametric axis is 'I'. Its moment of inertia about a tangent in the plane is
- A \(2 \cdot 5 \mathrm{I}\)
- B \(3 \cdot 0 \mathrm{I}\)
- C \(3 \cdot 5 \mathrm{I}\)
- D 4 I
Answer & Solution
Correct Answer
(C) \(3 \cdot 5 \mathrm{I}\)
Step-by-step Solution
Detailed explanation
\(I = \frac{2}{5} m R^2\) \(I_{tangent} = I + m R^2\)
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