MHT CET · Physics · Laws of Motion
The mass of the lift is 200 kg , when it ascends with an acceleration of \(4 \mathrm{~m} / \mathrm{s}^2\) then the tension in the cable supporting the lift will be [Given: Acceleration due to gravity \(\left.g=10 \mathrm{~m} / \mathrm{s}^2\right]\)
- A 800 N
- B 2800 N
- C 4200 N
- D 2000 N
Answer & Solution
Correct Answer
(B) 2800 N
Step-by-step Solution
Detailed explanation
The equation of motion for the lift is:
\(\begin{aligned}
& \mathrm{T}-\mathrm{ma}=\mathrm{mg} \\
& \mathrm{~T}=\mathrm{m}(\mathrm{~g}+\mathrm{a}) \\
& =200(10+4) \\
& \mathrm{T}=2800 \mathrm{~N}
\end{aligned}\)
\(\begin{aligned}
& \mathrm{T}-\mathrm{ma}=\mathrm{mg} \\
& \mathrm{~T}=\mathrm{m}(\mathrm{~g}+\mathrm{a}) \\
& =200(10+4) \\
& \mathrm{T}=2800 \mathrm{~N}
\end{aligned}\)
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