MHT CET · Physics · Gravitation
The magnitude of gravitational potential energy of a body at a distance ' \(R\) ' from the centre of the earth is ' \(E\) '. Its weight at a distance ' \(1.5 R\) ' from the centre of the earth is
- A \(\frac{2 E}{9 R}\)
- B \(\frac{4 \mathrm{E}}{5 \mathrm{R}}\)
- C \(\frac{4 E}{9 R}\)
- D \(\frac{2 \mathrm{E}}{7 \mathrm{R}}\)
Answer & Solution
Correct Answer
(C) \(\frac{4 E}{9 R}\)
Step-by-step Solution
Detailed explanation
\(E = \frac{GMm}{R}\) \(GMm = ER\)
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