MHT CET · Physics · Electromagnetic Induction
The magnetic potential energy stored in certain inductor is \(64 \times 10^{-3} \mathrm{~J}\), when the current in the inductor is 80 mA . This inductor is of inductance
- A 0.20 H
- B 2.0 H
- C 20 H
- D 200 H
Answer & Solution
Correct Answer
(C) 20 H
Step-by-step Solution
Detailed explanation
Energy stored in inductor, \(\mathrm{E}=\frac{1}{2} \mathrm{LI}^2\)
\(\therefore \quad L=\frac{2 \mathrm{E}}{\mathrm{I}^2}=\frac{2 \times 64 \times 10^{-3}}{\left(80 \times 10^{-3}\right)^2}=20 \mathrm{H}\)
\(\therefore \quad L=\frac{2 \mathrm{E}}{\mathrm{I}^2}=\frac{2 \times 64 \times 10^{-3}}{\left(80 \times 10^{-3}\right)^2}=20 \mathrm{H}\)
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