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MHT CET · Physics · Electromagnetic Induction

The magnetic flux through a coil of resistance \(R\) changes by an amount \(\Delta \phi\) in time \(\Delta t\). The total quantity of induced electric charge \(Q\) is

  1. A \(\frac{\Delta \phi}{\Delta t}\)
  2. B \(-\frac{\Delta \phi}{\Delta t}+R\)
  3. C \(\frac{\Delta \phi}{R}\)
  4. D \(\frac{\Delta \phi}{\Delta t} \times R\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\Delta \phi}{\Delta t} \times R\)

Step-by-step Solution

Detailed explanation

From Faraday's law of EMI, emf induced in the circuit is given by,
\(e=-\frac{\Delta \phi}{\Delta t}\)
And if \(R\) is the resistance in the circuit then it becomes,
\(\begin{aligned} & I=\frac{e}{R} \\ & \quad \Rightarrow I=-\frac{\Delta \phi}{\Delta t \cdot R}\end{aligned}\)
So, the total amount of charge passing through the circuit will become,
\(\begin{aligned} & \because \Delta Q=I \times \Delta t \\ & \Rightarrow \Delta Q=-\frac{\Delta \phi}{\Delta t \cdot R} \cdot \Delta t \\ & \Rightarrow \Delta Q=-\frac{\Delta \phi}{R}\end{aligned}\)
So, the total amount of charge passing through the circuit is given by \(\frac{\Delta \phi}{R}\)