MHT CET · Physics · Electromagnetic Induction
The magnetic flux through a circuit of resistance ' \(R\) ' changes by an amount \(\Delta \phi\) in the time \(\Delta t\). The total quantity of electric charge ' \(Q\) ' which passes during this time through any point of the circuit is
- A \(-\frac{\Delta \phi}{\Delta \mathrm{t}}+\mathrm{R}\)
- B \(\frac{\Delta \phi}{\mathrm{R}}\)
- C \(\frac{\Delta \phi}{\Delta t}\)
- D \(\frac{\Delta \phi}{\Delta \mathrm{t}} \times \mathrm{R}\)
Answer & Solution
Correct Answer
(B) \(\frac{\Delta \phi}{\mathrm{R}}\)
Step-by-step Solution
Detailed explanation
According to Faraday's law of electromagnetic induction,
\(\begin{aligned}
& \varepsilon=\frac{\Delta \phi}{\Delta t} \\
& I R=\frac{\Delta \phi}{\Delta t} \\
& I=\frac{\Delta \phi}{\Delta t \times R} \\
& I \times \Delta t=\frac{\Delta \phi}{R}
\end{aligned}\)
\(\therefore \quad\) The total quantity of electric charge passing through the circuit is
\(\mathrm{Q}=\frac{\Delta \phi}{\mathrm{R}}\)
\(\begin{aligned}
& \varepsilon=\frac{\Delta \phi}{\Delta t} \\
& I R=\frac{\Delta \phi}{\Delta t} \\
& I=\frac{\Delta \phi}{\Delta t \times R} \\
& I \times \Delta t=\frac{\Delta \phi}{R}
\end{aligned}\)
\(\therefore \quad\) The total quantity of electric charge passing through the circuit is
\(\mathrm{Q}=\frac{\Delta \phi}{\mathrm{R}}\)
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