MHT CET · Physics · Magnetic Effects of Current
The magnetic field intensity inside current carrying solenoid is \(\mathrm{H}=2.4 \times 10^3 \mathrm{~A} / \mathrm{m}\). If length and number of turns of a solenoid is 15 cm and 60 turns respectively. The current flowing in the solenoid is
- A 4 A
- B 6 A
- C \(\quad 0.6 \mathrm{~A}\)
- D 60 A
Answer & Solution
Correct Answer
(B) 6 A
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & B=\frac{\mu_0 \mathrm{NI}}{\mathrm{L}} \\ & \mu_0 \mathrm{H}=\frac{\mu_0 \mathrm{NI}}{\mathrm{L}} \\ & I=\frac{\mathrm{HL}}{\mathrm{n}}=\frac{2.4 \times 10^3 \times 15 \times 10^{-2}}{60}=6 \mathrm{~A}\end{aligned}\)
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