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MHT CET · Physics · Magnetic Effects of Current

The magnetic field at a point \(\mathrm{P}\) situated at perpendicular distance ' \(R\) ' from a long straight wire carrying a current of \(12 \mathrm{~A}\) is \(3 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^2\). The value of ' \(R\) ' in \(\mathrm{mm}\) is \(\left[\mu_0=4 \pi \times 10^{-7} \mathrm{~Wb} / \mathrm{Am}\right]\)

  1. A \(0.08\)
  2. B \(0.8\)
  3. C \(8\)
  4. D \(80\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(80\)

Step-by-step Solution

Detailed explanation

Using Biot-Savart's Law,
\(\begin{aligned}
\mathrm{B} & =\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{R}} \\
\therefore \quad \mathrm{R} & =\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{B}} \\
& =\frac{4 \pi \times 10^{-7} \times 12}{2 \pi \times 3 \times 10^{-5}} \\
& =8 \times 10^{-2} \mathrm{~m} \\
& =80 \mathrm{~mm}
\end{aligned}\)