MHT CET · Physics · Dual Nature of Matter
The light of wavelength \(\lambda^{\prime}\) incident on the surface of metal having work function \(\phi\) emits the electrons. The maximum velocity of electrons emitted is \((c=\) velocity of light, h=Planck's constant, m=mass of electron \()\)
- A \(\left[\frac{2(\mathrm{~h} \mathrm{C}-\phi)}{\mathrm{m} \lambda}\right]\)
- B \(\left[\frac{2(\mathrm{~h} \mathrm{c}-\lambda \phi)}{\mathfrak{m \lambda}}\right]^{\frac{1}{2}}\)
- C \(\left[\frac{2(h \mathrm{C}-\lambda)}{m \lambda}\right]^{\frac{1}{2}}\)
- D \(\left[\frac{2(\mathrm{~h} \mathrm{v}-\phi) \lambda}{\mathrm{mC}}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\frac{2(\mathrm{~h} \mathrm{c}-\lambda \phi)}{\mathfrak{m \lambda}}\right]^{\frac{1}{2}}\)
Step-by-step Solution
Detailed explanation
(C)
\(\mathrm{hv}-\phi=\mathrm{E}_{\max }=\frac{1}{2} \mathrm{mv}^{2}\)
\(\frac{\mathrm{hc}}{\lambda}-\phi=\frac{1}{2} \mathrm{mv}^{2}\)
\(\mathrm{v}^{2}=2 \frac{(\mathrm{hc}-\lambda \phi)}{\lambda \mathrm{m}}\)
\(\mathrm{hv}-\phi=\mathrm{E}_{\max }=\frac{1}{2} \mathrm{mv}^{2}\)
\(\frac{\mathrm{hc}}{\lambda}-\phi=\frac{1}{2} \mathrm{mv}^{2}\)
\(\mathrm{v}^{2}=2 \frac{(\mathrm{hc}-\lambda \phi)}{\lambda \mathrm{m}}\)
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