MHT CET · Physics · Waves and Sound
The length of closed and open pipe is same. The ratio of frequency of \(\mathrm{n}^{\text {th }}\) overtone for closed pipe to that of open pipe is (Neglect end correction)
- A \(\frac{(2 n+1)}{2(n+1)}\)
- B \(\frac{(\mathrm{n}+1)}{(2 \mathrm{n}+1)}\)
- C \(\frac{(2 n-1)}{2(n+1)}\)
- D \(\frac{(n-1)}{2(n+1)}\)
Answer & Solution
Correct Answer
(A) \(\frac{(2 n+1)}{2(n+1)}\)
Step-by-step Solution
Detailed explanation
\(f_{n,closed} = \frac{(2n+1)v}{4L}\) \(f_{n,open} = \frac{(n+1)v}{2L}\)
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